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Take Me Back (Leave Me There) by Cody Johnson - 90 BPM & Key 4B
90 BPM

Take Me Back (Leave Me There)

专辑: Unknown Album 发布日期: 29 May 2026 流派: 未知

"Take Me Back (Leave Me There)" by Cody Johnson has a tempo of 90 BPM. The track is composed in the key of G♯/A♭ Major (4B).

0:00 / 0:30

BPM

90

每分钟节拍数

调性 (Camelot)

4B

G♯/A♭ Major

拍号

N/A

拍号

  • 时长 3:20
  • 能量 34%
  • 可舞性 N/A
  • 积极度 (Valence) N/A
  • 响度 N/A
  • 发布日期 29 May 2026
在Spotify上查看

音频特征

Take Me Back (Leave Me There)

调性信息

4B
  • Camelot: 4B
  • 调性: G♯/A♭ Major
  • 关系调: F Minor

最佳匹配 (和声混音)

BPM历史记录

90 BPM

1:45

段落分解

详细段落分析暂不可用。

Track Insights

Tempo & Energy

At 90 BPM, "Take Me Back (Leave Me There)" sits in a mid-tempo range, making it versatile for many playlists.

Musical Key

The musical key of "Take Me Back (Leave Me There)" by Cody Johnson is G♯/A♭ Major, which corresponds to 4B on the Camelot wheel.

Harmonic Mixing

For harmonic mixing, songs in the keys of 3B, 5B, 4A will transition perfectly into "Take Me Back (Leave Me There)".

歌词

暂无歌词。

常见问题

Take Me Back (Leave Me There) 的BPM是多少?
曲目 Take Me Back (Leave Me There) 的节奏是 90 BPM。
Take Me Back (Leave Me There) 的调性是什么?
这首歌是以 4B 调演奏的。
Take Me Back (Leave Me There) 有多长?
这首歌的时长为 3:20。
Take Me Back (Leave Me There) 属于什么流派?
The song Take Me Back (Leave Me There) belongs to the 未知 genre.

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